42f+49=-9f^2

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Solution for 42f+49=-9f^2 equation: 



42f+49=-9f^2

We move all terms to the left:

42f+49-(-9f^2)=0

We get rid of parentheses

9f^2+42f+49=0

a = 9; b = 42; c = +49;
Δ = b2-4ac
Δ = 422-4·9·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{-42}{18}=-2+1/3$

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